Yes, and Ulf takes this change in traction force into account by using the speed in his traction force calculation (F=P/v) instead of a fixedly calculated tire radius (and then F=M/r, which is worse because nothing is balanced and you need the gear ratio, as Ulf already mentioned).
To my previous post:
'When I said 'at 0% gradient,' I just meant that it's difficult to estimate.'
And when I said 'new tires,' I actually just meant that the rolling circumference should correspond to the calculated rolling circumference (especially if you're already opting out of using the speedometer to compensate).
It's easy to make mistakes during the test, such as using smaller tires, setting the initial speed to 50, and then overlooking a 1% incline, which could lead to a perceived 8% increase in performance.
I was already aware that

this wouldn't happen to you (Ulf), it was just a note for laypeople who believe they have at least 100% more power, and who don't consider that in a test, they're not on a slope but rather already in free fall .
Best regards,