Gremlin wrote: |
The most important parameter for optocouplers, besides the breakdown voltage (which is likely less critical here), is the transfer ratio. This is roughly comparable to the current gain of a transistor.
Therefore, use CNY17-3; the standard CNY17 doesn't have a high enough current transfer ratio, and there's a possibility that the signal levels won't be sufficient.
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Hi.
Thank you for your explanations.
I'm going to have some fun(?) and build this thing according to
my ideas.
Okay, I'll measure the initial levels "in a dry run" and, if necessary, adjust the resistors so that "low" is truly "low."
For example, I find the way transistor T2 is controlled, with only 140 kΩ from the K-line, to be somewhat crude.
As long as the K-line has more than 0.6 volts, the optocoupler for the direction Auto --> PC will still be slightly activated, which (depending on the coupling factor

) could confuse the PC as a receiver.
I suspect that the tip mentioned in this post, to replace R7 with a 10k resistor, is based on the idea that the onboard electronics are more likely to reliably maintain a voltage below 0.6 volts with a 10k resistor than with a 1k resistor.
If you simply add a resistor in parallel with the base-emitter path of transistor T2 (e.g., 15k ohms), the high-low transition will switch cleanly towards the positive supply voltage at approximately 6 volts.
Quote: |
| Diodes 1N4007 (yes, yes... from the electronics kit). I wouldn't use 4148; 100V spikes at an interface are nothing special and not rare... |
It might be true, but the diodes I'm referring to are connected in an antiparallel configuration to the opto-LEDs, and these opto-LEDs would have to short-circuit or convert voltage "peaks" (for the 1N4148 diodes) of over 2 volts into short pulses.
Therefore, to me, 1 N 4004 still seem like atomic bombs against sparrows

.