Boost Increase: 10ct Tuning - The Slow Way

Hello,

I have so far achieved a 10% boost in turbocharger pressure by approximately 0.1 bar using a diode.
I no longer remember exactly what type of diode it is, but it definitely produces a voltage drop of approximately 0.3 V starting from a current of 5 mA.

"Now I'm not satisfied with just 0.1 bar of boost pressure. Soon, I'll be installing larger injectors from AEL, and then I want to run at 1.2 bar."

Avoso is here https://community.dieselschrauber.org/en/viewtopic.php?t=1308&highlight=.
described how to implement an adjustable boost in charging pressure. I haven't tried this yet, but I plan to.
Essentially, a variable resistor is simply inserted into the voltage supply of the pressure sensor.

To minimize overshoot as much as possible, I'm considering a further modification, but I don't understand enough about electronics to confidently design and build a circuit for it myself.

Question:
Couldn't a capacitor be connected in parallel with the pre-set resistor? As far as I know, capacitors exhibit the following conductivity behavior: When a capacitor is completely discharged, current flows through it, but this current flow decays exponentially over time. Therefore, if no more current can flow through the capacitor, the current must flow entirely through the variable resistor, thus allowing the pressure increase to be fully controlled.
Of course, this should only start working above a certain boost pressure, otherwise the capacitor would start charging even at idle and become non-conductive.

The goal is to have the boost pressure build up to the standard value (1 bar) using normal control behavior. However, once the boost pressure reaches 1 bar, the system should simulate a lower boost pressure to the control unit, so that the control unit gradually adjusts to a boost pressure of 1.2 bar.

It would be great if one of the electronics experts here in the forum could comment on this.

Have you ever heard of chip tuning?
It's much easier to achieve with this.
"You know that simply increasing the boost pressure alone achieves absolutely nothing."
It has a lower efficiency.

If you still want to adjust the boost pressure yourself, you can get a MAP sensor.
Solder it into your control unit. You can find information about this using Google.

Hello Steffarn,

Whoever can read has a clear advantage. javascript:emoticon('')
Certainly, you also know that an ASV has a MAP sensor in the charge air path. Therefore, there's no need to solder anything in the control unit. Or should I solder in an additional pressure sensor into the control unit javascript:emoticon('')?

Quote:

"You know that simply increasing the boost pressure alone achieves absolutely nothing." It has a lower efficiency.

As I mentioned, nozzles from AEL are also supposed to be included.
Currently, I have an adjustable 3-potentiometer box installed, and it's sufficient for adjusting the extra fuel injection amount. It's clear that it could be even better with chip tuning.

Best regards, Georg.

Did you mean transistor?

When current flows through a capacitor, it is...
In my humble opinion, it's broken!

When you create a system or process that is eligible for funding...
'Effort! Get rid of those overachievers, then write to me.'

Why would you subject a VNT15 to such hardship? Just get a [mention the alternative].
'Get a VNT 17, or even better, a 20.'

Did you mean transistor, or?

When current flows through a capacitor, it is...
In my humble opinion, it's broken!

When you create a system or process that is eligible for funding...
'Effort! Get rid of those overachievers, then write to me.'

Why would you subject a VNT15 to such hardship? Just get a

Hello 'ObenbeiMutti',
Alternating current always flows through a capacitor, while direct current only flows until the capacitor is charged.
Best regards,
Günther.

Inspired by the ice cream cart that I vaguely remember, it is supposed to be placed in a...
The circuit seems to be working as you intended.

But nothing is actually flowing through it; think about the school experiments with the plate capacitor.
If the potential difference became large enough to cause a spark, it would be broken.

Hi.

Georg_G wrote:

... Wouldn't it be possible to connect a capacitor in parallel with the pre-set resistor? As far as I know, capacitors exhibit the following conductivity behavior: When a capacitor is completely discharged, current flows through it, but this current flow decreases exponentially over time. Therefore, if no more current can flow through the capacitor, the current must flow entirely through the variable resistor, and thus the pressure increase caused by the charging process will be fully effective. Of course, this should only start working above a certain boost pressure, otherwise the capacitor would start charging even at idle and become non-conductive. The goal is to have the boost pressure build up to the standard value (1 bar) using normal control behavior. However, once the boost pressure reaches 1 bar, the system should simulate a lower boost pressure to the control unit, so that the control unit gradually adjusts to a boost pressure of 1.2 bar. It would be great if one of the electronics experts here in the forum could write something about it.

It would generally work. A current flows whenever the potentials at the capacitor electrodes change. That is, with a constant voltage of 'x' volts, where 'x' is less than the breakdown voltage, no current will flow. -> Your circuit is called a high-pass filter. You can find good descriptions of it online, and I think there are also online calculators with nice diagrams.

If you adjust the time constant to be on the order of the settling time, the control system should perform better.
http://www.computerbase.de/lexikon/Zeitkonstante
You just need to make sure that the control loop remains stable. Further basics:
http://141.99.140.157/d/imr5/RTKurs/13seite/13seite.html

Best regards, Rainer.

Hello 'ObenbeiMutti',
You have a private message.
Best regards,
Günther.

@Rainer

How does he plan to fine-tune it so that it fits perfectly, or when will the capacitor fail, and when will the resistor dissipate the excess energy? How quickly does a capacitor discharge? With short gas changes, this won't work. Should he use a transistor that he can switch on or off depending on the control signal?
Or am I just imagining things?

@Günther

'No offense, but 'current flowing through the capacitor' is syntactically incorrect. What goes in on one side *must* come out on the exact same side, otherwise it's broken, honestly.'

@Rainer

How does he plan to fine-tune it so that it fits perfectly, or when will the capacitor fail, and when will the resistor dissipate the excess energy? How quickly does a capacitor discharge? With short gas changes, this won't work. Should he use a transistor that he can switch on or off depending on the control signal?
Or am I just imagining things?

@Günther

'No offense, but 'current flowing through the capacitor' is syntactically incorrect. What goes in on one side *must* come out on exactly the same side, otherwise it's broken, honestly.'}

Hello,
You can quite easily compare a capacitor to a balloon!
Best regards,
Günther.

PS: (Of course, I meant a rather large capacitor in the private message!)

ObenbeiMutti wrote:

@Rainer How does he plan to fine-tune it so that it fits perfectly, or when will the capacitor burst...?

The capacitor doesn't explode; it's supposed to withstand 5V.

http://www.elektronik-kompendium.de/sites/grd/0205301.htm

Hi,

As long as you don't exceed the capacitor's maximum rated voltage, nothing will explode. Therefore, the comparison to a balloon is only very, very limited and not entirely accurate.

If a capacitor were to explode due to continuous "charging," every PC power supply and virtually every electronic device would fail.

Best regards,

Jan.

Hello,
The balloon won't burst as long as the pressure (which is equivalent to the voltage in a capacitor) isn't too high!
Best regards,
Günther.

You can interpret that however you want...

There is no electron flow THROUGH the capacitor.
However, when the electrodes ('plates') are being switched, electrons are being moved, which constitutes an electric current. This current can be easily measured from the outside using an ammeter.

'Such current flows can reach drastic magnitudes. Many hobbyists prematurely choose field-effect transistors because of their 'lossless' control. This is true in the static range (where no gate current flows). However, in dynamic operation (audio, PWM), currents in the ampere range can occur, which can then drastically overload the preceding circuitry.'

A capacitor connected in parallel with a resistor initially introduces a certain time delay. However, this delay occurs in BOTH directions. Therefore, the pressure would build up more slowly, but also decrease more slowly.

However, this entire process will not work if you reduce the operating voltage of the sensor. This can cause the sensor to operate in an undefined range.
Typically, the output voltage of the sensor is reduced using a voltage divider (resistor from the output to ground, do not overload the sensor output!).
Similarly, a capacitor placed in parallel would integrate the changes and provide a time delay in both directions.

Since the entire system needs to react dynamically starting from a certain pressure level (equal to the output voltage), it's no longer possible to achieve this with passive components. More effort is required here.

CU.

Hello,
I'm from the electrical engineering field, and I intentionally didn't want to delve too deeply into the topic here (it's just ----!).
In FET circuits, the 'problem' is often simply shifted from the output stage to the input stage, because the gate capacitance can also cause issues at higher frequencies, especially when fast switching is required.
Best regards,
Günther

PS: A capacitor connected in parallel with the resistor 'accelerates' the signal; only an RC circuit integrates (averages) the signal.

PS: A capacitor connected in parallel with the resistor 'accelerates' the signal; only an RC circuit integrates (delays)

You are forgetting about the sensor's output impedance and the controller's input impedance!

CU.